Name: Saggi Mizrahi • ID: 032493124 • Group: מעוף א' • Date: November 12, 2013
/* parity.cpp
* This program calculates the parity of an ID.
*
* Saggi Mizrahi 05 November 2013
*/
#include <iostream>
using namespace std;
/* Calculate the parity of an IDS
* Input: An ID without leading 0 or parity.
* Output: ID including parity.
*/
int main()
{
// declaration of variables
int ID = -1;
int digit = -1;
int digitMultiple = -1;
int parity = -1;
int multiplier = 2;
int digitSum = 0;
// Get user input
cout << "please enter your ID: ";
cin >> ID;
// Calculate
for(int tmp = ID; tmp > 0; tmp /= 10) {
digit = tmp % 10;
digitMultiple = digit * multiplier;
// Sum up the digits of the multiple
for (int tmp = digitMultiple; tmp > 0; tmp /= 10) {
digitSum += tmp % 10;
}
// flip the multiplier
multiplier = multiplier == 1 ? 2 : 1;
}
parity = 10 - (digitSum % 10);
// outputting the result
cout << ID << parity << endl;
}Check given example:
please enter your ID: 56287
562876
Check my ID:
please enter your ID: 3249312
32493124
/* equasion.cpp
* This program finds the number of solutions for Ax+By+Cz=D where
* -N/2 <= x, y, z <= N/2.
*
* Saggi Mizrahi 12 November 2013
*/
#include <iostream>
using namespace std;
/* Find the number of solutions for Ax+By+Cz=D and print it out.
* Input: 5 number A B C D and N.
* Output: Summery of the input the number of solution and an example of a
* solution.
*/
int main()
{
// declaration of variables
int a = -1;
int b = -1;
int c = -1;
int d = -1;
int n = -1;
int min = 0;
int max = 0;
int remainder = 0;
int numSolutions = 0;
int correctX = 0;
int correctY = 0;
int correctZ = 0;
// Get user input
cout << "please enter 5 numbers: ";
cin >> a >> b >> c >> d >> n;
// Calculate range
min = -1 * (n / 2);
max = n / 2;
// Find solutions
for (int x = min; x <= max; x++) {
for (int y = min; y <= max; y++) {
remainder = d;
remainder -= a * x;
remainder -= b * y;
if ((remainder % c) == 0) {
remainder /= c;
if (remainder >= min && remainder <=max) {
numSolutions++;
correctX = x;
correctY = y;
correctZ = remainder;
}
}
}
}
// outputting the result
cout << "There are " << numSolutions << " solutions for " <<
"(" << a << " * x) + (" << b << " * y) + (" << c <<
" * z) = " << d << endl;
cout << "Where: " << min << " <= x, y, z <= " << max << endl;
cout << "One such solution is (" << correctX << ", " << correctY <<
", " << correctZ << ")" << endl;
}Check given example:
please enter 5 numbers: 2 -3 -1 5 4
There are 6 solutions for (2 * x) + (-3 * y) + (-1 * z) = 5
Where: -2 <= x, y, z <= 2
One such solution is (2, 0, -1)
please enter 5 numbers: 4 -18 -1 30 10
There are 6 solutions for (4 * x) + (-18 * y) + (-1 * z) = 30
Where: -5 <= x, y, z <= 5
One such solution is (4, -1, 4)
please enter 5 numbers: 4 -18 -1 30 100
There are 573 solutions for (4 * x) + (-18 * y) + (-1 * z) = 30
Where: -50 <= x, y, z <= 50
One such solution is (50, 12, -46)
please enter 5 numbers: 4 -18 -1 30 1000
There are 55723 solutions for (4 * x) + (-18 * y) + (-1 * z) = 30
Where: -500 <= x, y, z <= 500
One such solution is (500, 137, -496)
/* romansA.cpp
* This program prints out an input number in roman numerals.
*
* Saggi Mizrahi 12 November 2013
*/
#include <iostream>
using namespace std;
/* Print a number in roman numerals.
* Input: A number.
* Output: The number in roman numerals.
*/
int main()
{
// declaration of variables
int number = -1;
// Get user input
cout << "please enter a number: ";
cin >> number;
// Print out number
while(number >= 1000) {
cout << "M";
number -= 1000;
}
while(number >= 500) {
cout << "D";
number -= 500;
}
while(number >= 100) {
cout << "C";
number -= 100;
}
while(number >= 50) {
cout << "L";
number -= 50;
}
while(number >= 10) {
cout << "X";
number -= 10;
}
while(number >= 5) {
cout << "V";
number -= 5;
}
while(number >= 5) {
cout << "V";
number -= 5;
}
while(number > 0) {
cout << "I";
number--;
}
cout << endl;
}please enter a number: 9
VIIII
please enter a number: 10
X
please enter a number: 2013
MMXIII
please enter a number: 1986
MDCCCCLXXXVI
/* romansB.cpp
* This program prints out an input roman number in arabaic numerals.
*
* Saggi Mizrahi 12 November 2013
*/
#include <iostream>
using namespace std;
/* Print a roman number in arabaic numerals.
* Input: A roman number.
* Output: The roman number in arabaic numerals.
*/
int main()
{
// decleration of constants
const int M_VALUE = 1000;
const int D_VALUE = 500;
const int C_VALUE = 100;
const int L_VALUE = 50;
const int X_VALUE = 10;
const int V_VALUE = 5;
const int I_VALUE = 1;
const char EOI = '\n';
// declaration of variables
char c;
char lastChar = 'E';
int result = 0;
int lastValue = M_VALUE;
int value = -1;
int singletonCount = 0;
int quadroCount = 0;
// Get user input
cout << "please enter a number: ";
while ((c = cin.get()) != EOI) {
if (lastChar != c) {
singletonCount = 0;
quadroCount = 0;
}
switch (c) {
case 'M':
value = M_VALUE;
break;
case 'D':
singletonCount++;
value = D_VALUE;
break;
case 'C':
quadroCount++;
value = C_VALUE;
break;
case 'L':
singletonCount++;
value = L_VALUE;
break;
case 'X':
quadroCount++;
value = X_VALUE;
break;
case 'V':
singletonCount++;
value = V_VALUE;
break;
case 'I':
quadroCount++;
value = I_VALUE;
break;
default:
cout << "Invalid input, unknown value for '" <<
c << "'" << endl;
return -1;
}
if (value > lastValue) {
cout << "Invalid input, '" << c << "' after '" <<
lastChar << "'" << endl;
return -1;
};
if (singletonCount > 1) {
cout << "Invalid input, '" << c <<
"' can only appear once" << endl;
return -1;
}
if (quadroCount > 4) {
cout << "Invalid input, '" << c <<
"' can only appear up to four times" << endl;
return -1;
}
result += value;
lastValue = value;
lastChar = c;
}
// Print out result
cout << result << endl;
return 0;
}please enter a number: VIII
8
please enter a number: X
10
please enter a number: XM
Invalid input, 'M' after 'X'
please enter a number: LL
Invalid input, 'L' can only appear once
please enter a number: XXXXXX
Invalid input, 'X' can only appear up to four times
a)
main: k = a
f: k = a
main: k = ab)
main: k = a
f: k = a
main: k = 3c)
main: k = a
g: k = a
g: k = 7
main: k = ad)
main: k = a
g: k = a
g: k = 7
main: k = 7e)
return 0
return 1 f)
h1: k = 12
h1: k = 0
return 1
return 1g)
expected primary-expression before int
/* maxmin.cpp
* This program prints out the largest and smallest of 3 numbers
*
* Saggi Mizrahi 12 November 2013
*/
#include <iostream>
using namespace std;
double maximum(double a, double b, double c);
double minimum(double a, double b, double c);
double maximum(double a, double b, double c) {
if (a > b) {
b = a;
}
if (b > c) {
return b;
} else {
return c;
}
}
double minimum(double a, double b, double c) {
return -1 * maximum(-1 * a, -1 * b, -1 * c);
}
/* Prints out the largest and smallest of 3 number.
* Input: 3 numbers.
* Output: the largest and smallest value entered.
*/
int main()
{
// declaration of variables
double a, b, c;
// Get user input
cout << "please enter 3 numbers: ";
cin >> a >> b >> c;
cout << "min: " << minimum(a, b, c) << ", max: " << maximum(a, b, c) <<
endl;
return 0;
}